If A=023-4, kA=03a2b24, then the values of k, a, b are respectively

03a2b24=kA=k023-4=02k3k-4k⇒3a = 2k, 2b = 3k, 24 = - 4k ⇒k = - 6, a = - 4, b = - 9.

If A=023-4, kA=03a2b24, then the values of k, a, b are respectively

03a2b24=kA=k023-4=02k3k-4k⇒3a = 2k, 2b = 3k, 24 = - 4k ⇒k = - 6, a = - 4, b = - 9.

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If $A = [\begin{matrix} 0 & 2 \\ 3 & - 4 \end{matrix}], k A = [\begin{matrix} 0 & 3 a \\ 2 b & 24 \end{matrix}]$ , then the values of k, a, b are respectively

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-6, -12, -18

-6, 4, 9

-6, -4, -9

-6, 12, 18

answer is C.

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$[\begin{matrix} 0 & 3 a \\ 2 b & 24 \end{matrix}] = k A = k [\begin{matrix} 0 & 2 \\ 3 & - 4 \end{matrix}] = [\begin{matrix} 0 & 2 k \\ 3 k & - 4 k \end{matrix}]$

$\Rightarrow$ 3a = 2k, 2b = 3k, 24 = - 4k $\Rightarrow$ k = - 6, a = - 4, b = - 9.

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If A=023-4, kA=03a2b24, then the values of k, a, b are respectively

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If $A = [\begin{matrix} 0 & 2 \\ 3 & - 4 \end{matrix}], k A = [\begin{matrix} 0 & 3 a \\ 2 b & 24 \end{matrix}]$ , then the values of k, a, b are respectively