If A=023-4, kA=03a2b24 then the values of k, a, b are respectively

A=023-4, kA=03a2b24 02k3k-4k=03a2b24 -4k=24⇒k=-6 2k=3a⇒a=-4 3k=2b⇒b=-9

If A=023-4, kA=03a2b24 then the values of k, a, b are respectively

A=023-4, kA=03a2b24 02k3k-4k=03a2b24 -4k=24⇒k=-6 2k=3a⇒a=-4 3k=2b⇒b=-9

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If $A = (\begin{matrix} 0 & 2 \\ 3 & - 4 \end{matrix}), kA = (\begin{matrix} 0 & 3 a \\ 2 b & 24 \end{matrix})$ then the values of k, a, b are respectively

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–6, –12, –18

–6, 4, 9

–6, –4, –9

–6, 12, 18

answer is C.

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$A = (\begin{matrix} 0 & 2 \\ 3 & - 4 \end{matrix}), kA = (\begin{matrix} 0 & 3 a \\ 2 b & 24 \end{matrix})$

$(\begin{matrix} 0 & 2 k \\ 3 k & - 4 k \end{matrix}) = (\begin{matrix} 0 & 3 a \\ 2 b & 24 \end{matrix}) - 4 k = 24 \Rightarrow k = - 6 2 k = 3 a \Rightarrow a = - 4 3 k = 2 b \Rightarrow b = - 9$

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If A=023-4, kA=03a2b24 then the values of k, a, b are respectively

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If $A = (\begin{matrix} 0 & 2 \\ 3 & - 4 \end{matrix}), kA = (\begin{matrix} 0 & 3 a \\ 2 b & 24 \end{matrix})$ then the values of k, a, b are respectively