If A=023−4 , kA=03a2b24 then the values of k, a, b are respectively

02k3k−4k =03a2b24 ∴k=−6,3a=−12⇒a=−4 2b=3k⇒b=−9∴k=−6,a=−4,b=−9

If A=023−4 , kA=03a2b24 then the values of k, a, b are respectively

02k3k−4k =03a2b24 ∴k=−6,3a=−12⇒a=−4 2b=3k⇒b=−9∴k=−6,a=−4,b=−9

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If $A = (\begin{matrix} 0 & 2 \\ 3 & - 4 \end{matrix}), k A = (\begin{matrix} 0 & 3 a \\ 2 b & 24 \end{matrix})$ then the values of $k, a, b$ are respectively

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$- 6, 12, 18$

$- 6, - 12, - 18$

$- 6, 4, 9$

$- 6, - 4, - 9$

answer is C.

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$(\begin{matrix} 0 & 2 k \\ 3 k & - 4 k \end{matrix}) = (\begin{matrix} 0 & 3 a \\ 2 b & 24 \end{matrix})$

$∴ k = - 6, 3 a = - 12 \Rightarrow a = - 4$

$2 b = 3 k \Rightarrow b = - 9$

$∴ k = - 6, a = - 4, b = - 9$

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If A=023−4 , kA=03a2b24 then the values of k, a, b are respectively

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If $A = (\begin{matrix} 0 & 2 \\ 3 & - 4 \end{matrix}), k A = (\begin{matrix} 0 & 3 a \\ 2 b & 24 \end{matrix})$ then the values of $k, a, b$ are respectively