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Q.

If A=11-2014231 and A3-3A2-5A=kI then k = .............

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a

3

b

2

c

1

d

4

answer is B.

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Detailed Solution

A2=11-2014231 11-2014231=1+0-41+1-6-2+4-20+0+80+1+120+4+42+0+22+3+3-4+12+1=-3-408138489

A3=A A2=11-2014231 11-28138489=-3+8-8-4+13-160+8-180+8+160+13+320+8+36-6+24+4-8+39+80+24+9=-3-7-10244544223933

A3-3A2-5A-I=-3-7-10244544223933-3 -3-408138489=5 11-2014231-100010001

-3+9-5-1-7+12-5-0-10-0+10-024-24-0-045-39-5-144-24-20-022-12-10-039-24-15-033-27-5-1=000000000=O

KI-I=Ok=1.

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