If A=1 1 11 1 11 1 1 Then |adj⁡A|=

A11=1111=1×1−1×1=0A12=1111=1×1−1×1=0A13=1111=1×1−1×1=0A21=1111=1×1−1×1=0A22=1111=1×1−1×1=0A23=1111=1×1−1×1=0A31=1111=1×1−1×1=0A32=1111=1×1−1×1=0A33=1111=1×1−1×1=0adj⁡A=A11 A12 A13A21 A22 A23A31 A32 A33∣or adj⁡A=0 0 00 0 00 0 0=0 0 00 0 00 0 0|adj⁡A|=0 0 00 0 00 0 0=0

If A=1 1 11 1 11 1 1 Then |adj⁡A|=

A11=1111=1×1−1×1=0A12=1111=1×1−1×1=0A13=1111=1×1−1×1=0A21=1111=1×1−1×1=0A22=1111=1×1−1×1=0A23=1111=1×1−1×1=0A31=1111=1×1−1×1=0A32=1111=1×1−1×1=0A33=1111=1×1−1×1=0adj⁡A=A11 A12 A13A21 A22 A23A31 A32 A33∣or adj⁡A=0 0 00 0 00 0 0=0 0 00 0 00 0 0|adj⁡A|=0 0 00 0 00 0 0=0

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If $A = |\begin{array}{lll} 1 1 1 \\ 1 1 1 \\ 1 1 1 \end{array}|$ Then $| adj A | =$

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Detailed Solution

$\begin{aligned} A_{11} = |\begin{array}{ll} 1 & 1 \\ 1 & 1 \end{array}| = 1 \times 1 - 1 \times 1 = 0 \\ A_{12} = |\begin{array}{ll} 1 & 1 \\ 1 & 1 \end{array}| = 1 \times 1 - 1 \times 1 = 0 \\ A_{13} = |\begin{array}{ll} 1 & 1 \\ 1 & 1 \end{array}| = 1 \times 1 - 1 \times 1 = 0 \\ A_{21} = |\begin{array}{ll} 1 & 1 \\ 1 & 1 \end{array}| = 1 \times 1 - 1 \times 1 = 0 \\ A_{22} = |\begin{array}{ll} 1 & 1 \\ 1 & 1 \end{array}| = 1 \times 1 - 1 \times 1 = 0 \end{aligned}$

$\begin{aligned} A_{23} = |\begin{array}{ll} 1 & 1 \\ 1 & 1 \end{array}| = 1 \times 1 - 1 \times 1 = 0 \\ A_{31} = |\begin{array}{ll} 1 & 1 \\ 1 & 1 \end{array}| = 1 \times 1 - 1 \times 1 = 0 \\ A_{32} = |\begin{array}{ll} 1 & 1 \\ 1 & 1 \end{array}| = 1 \times 1 - 1 \times 1 = 0 \\ A_{33} = |\begin{array}{ll} 1 & 1 \\ 1 & 1 \end{array}| = 1 \times 1 - 1 \times 1 = 0 \end{aligned}$