Q.

If A=1    1    11    1    11    1    1 Then |adjA|=

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a

7

b

0

c

3

d

5

answer is A.

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Detailed Solution

A11=1111=1×11×1=0A12=1111=1×11×1=0A13=1111=1×11×1=0A21=1111=1×11×1=0A22=1111=1×11×1=0

A23=1111=1×11×1=0A31=1111=1×11×1=0A32=1111=1×11×1=0A33=1111=1×11×1=0

adjA=A11    A12    A13A21    A22    A23A31    A32    A33

or adjA=0    0    00    0    00    0    0=0    0    00    0    00    0    0

|adjA|=0    0    00    0    00    0    0=0

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If A=1    1    11    1    11    1    1 Then |adj⁡A|=