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If $A = {1, 2, 3, \dots, 10}$ and $R = {(1, 2), (2, 4), (3, 6), (4, 8), (5, 10)}$ , then the set builder form of the relation $R$ is

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$R = {(x, y) / (x, y) \in A \times A; y = 2 x}$

$R = {(x, y) / (x, y) \in A \times A; y = x}$

$R = {(x, y) / (x, y) \in A \times A; x ∠ y}$

$R = {(x, y) / (x, y) \in A \times A; 2 y = x}$

answer is C.

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Detailed Solution

$A = {1, 2, 3, \dots, 10}$

$R = {(1, 2), (2, 4), (3, 6), (4, 8), (5, 10)}$

$R = {(x, y) / (x, y) \in A \times A; y = 2 x$

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