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Q.

If a=1, b=2 and the angle between a and b is 1200, then a+3b×3a-b2=..............

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a

200

b

400

c

100

d

300

answer is C.

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Detailed Solution

a+3b×3a-b2=3a×a-a×b+9b×a-3b×b2

=10b×a2=102b2a2sin2a, b=1002212sin21200=4003/22=300.

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