If A=22-32 and B=0-110, then (B−1A−1)−1=

A=22-32 and B=0-110(B−1A−1)−1=(A−1)−1(B−1)−1=AB=22−32 0−110=0+2−2+00+23+0=2-223

If A=22-32 and B=0-110, then (B−1A−1)−1=

A=22-32 and B=0-110(B−1A−1)−1=(A−1)−1(B−1)−1=AB=22−32 0−110=0+2−2+00+23+0=2-223

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If $A = [\begin{matrix} 2 & 2 \\ - 3 & 2 \end{matrix}]$ and $B = [\begin{matrix} 0 & - 1 \\ 1 & 0 \end{matrix}]$ , then ${(B^{- 1} A^{- 1})}^{- 1} =$

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$[\begin{matrix} - 2 & - 2 \\ - 2 & 3 \end{matrix}]$

$[\begin{matrix} 3 & 1 \\ 2 & 2 \end{matrix}]$

$[\begin{matrix} 2 & 1 \\ 2 & 3 \end{matrix}]$

$[\begin{matrix} 2 & - 2 \\ 2 & 3 \end{matrix}]$

answer is D.

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$A = [\begin{matrix} 2 & 2 \\ - 3 & 2 \end{matrix}]$ and $B = [\begin{matrix} 0 & - 1 \\ 1 & 0 \end{matrix}]$

${(B^{- 1} A^{- 1})}^{- 1} = {(A^{- 1})}^{- 1} {(B^{- 1})}^{- 1} = A B$

$= [\begin{matrix} 2 & 2 \\ - 3 & 2 \end{matrix}] [\begin{matrix} 0 & - 1 \\ 1 & 0 \end{matrix}]$

$= [\begin{matrix} 0 + 2 & - 2 + 0 \\ 0 + 2 & 3 + 0 \end{matrix}]$

$= [\begin{matrix} 2 & - 2 \\ 2 & 3 \end{matrix}]$

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If A=22-32 and B=0-110, then (B−1A−1)−1=

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If $A = [\begin{matrix} 2 & 2 \\ - 3 & 2 \end{matrix}]$ and $B = [\begin{matrix} 0 & - 1 \\ 1 & 0 \end{matrix}]$ , then ${(B^{- 1} A^{- 1})}^{- 1} =$