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Q.

If a2+b2+c2=-2  and  f(x)=1+a2x1+b2x1+c2x1+a2x1+b2x1+c2x1+a2x1+b2x1+c2x then f(x) is a polynomial of degree

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a

1

b

2

c

3

d

0

answer is B.

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Detailed Solution

Applying , C1C1+C2+C3 we get 

f(x)=11+b2x1+c2x11+b2x1+c2x11+b2x1+c2x

                       [using a2+b2+c2=-2]

Applying R2R2-R1 and R3R3-R1,we get 

f(x)=11+b2x1+c2x 01x0001-x =(1-x)2

which is a polynomial of degree 2.

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