IfA=32-1154-237,B=121212121 and 3A+2X=5B then X=

3A+2X=5B⇒2X=5B−3A=[5105105105105]−[96−331512−6921] X=12-4487-10-2111-16=-2247/2-5-111/21/2-8

IfA=32-1154-237,B=121212121 and 3A+2X=5B then X=

3A+2X=5B⇒2X=5B−3A=[5105105105105]−[96−331512−6921] X=12-4487-10-2111-16=-2247/2-5-111/21/2-8

AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

If $A = [\begin{matrix} 3 & 2 & - 1 \\ 1 & 5 & 4 \\ - 2 & 3 & 7 \end{matrix}], B = [\begin{matrix} 1 & 2 & 1 \\ 2 & 1 & 2 \\ 1 & 2 & 1 \end{matrix}] a n d 3 A + 2 X = 5 B t h e n X =$

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

$[\begin{matrix} \frac{4}{5} & 1 \\ \frac{9}{5} & - \frac{2}{5} \\ - \frac{4}{5} & - \frac{3}{5} \end{matrix}]$

$[\begin{matrix} 0 & 2 \\ 3 & 7 \\ 5 & 6 \end{matrix}]$

$[\begin{matrix} - 2 & 2 & 4 \\ \frac{7}{2} & - 5 & - 1 \\ \frac{11}{2} & \frac{1}{2} & - 8 \end{matrix}]$

$[\begin{matrix} 0 & - 2 \\ 3 & 7 \\ 5 & 6 \end{matrix}]$

answer is C.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

$3 A + 2 X = 5 B \Rightarrow 2 X = 5 B - 3 A = [\begin{matrix} 5 & 10 & 5 \\ 10 & 5 & 10 \\ 5 & 10 & 5 \end{matrix}] - [\begin{matrix} 9 & 6 & - 3 \\ 3 & 15 & 12 \\ - 6 & 9 & 21 \end{matrix}]$ $X = \frac{1}{2} [\begin{matrix} - 4 & 4 & 8 \\ 7 & - 10 & - 2 \\ 11 & 1 & - 16 \end{matrix}]$ = $[\begin{matrix} - 2 & 2 & 4 \\ 7 / 2 & - 5 & - 1 \\ 11 / 2 & 1 / 2 & - 8 \end{matrix}]$