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Q.

If a=3i+2j+k, b=i+j+2k and c=i+3j+3k then the angle between a and
the plane containing the face determined by b and c is

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a

sin-1914

b

cos-1914

c

sin-113

d

sin-123

answer is B.

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Detailed Solution

b×c=ijk112133=i(-3)-j(1)+k(2)as cosθ=a.(b×c)ab×c=-9-2+29+4+19+1+4=-914

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