If A={8,9,10} and B={1,2,3,4,5}, then the number of elements in A×A×B are

n(A×B×C×….)=n(A)×n(B)×n(C)×……n(A×A×B)=n(A)×n(A)×n(B) [∵n(A)=3,n(B)=5]=3×3×5=45

If A={8,9,10} and B={1,2,3,4,5}, then the number of elements in A×A×B are

n(A×B×C×….)=n(A)×n(B)×n(C)×……n(A×A×B)=n(A)×n(A)×n(B) [∵n(A)=3,n(B)=5]=3×3×5=45

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If $A = {8, 9, 10} and B = {1, 2, 3, 4, 5}$ , then the number of elements in $A \times A \times B$ are

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$\begin{array}{l} n (A \times B \times C \times \dots .) = n (A) \times n (B) \times n (C) \times \dots \dots \\ n (A \times A \times B) = n (A) \times n (A) \times n (B) \\ [∵ n (A) = 3, n (B) = 5] \\ = 3 \times 3 \times 5 = 45 \end{array}$

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If A={8,9,10} and B={1,2,3,4,5}, then the number of elements in A×A×B are

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If $A = {8, 9, 10} and B = {1, 2, 3, 4, 5}$ , then the number of elements in $A \times A \times B$ are