$\text{ If }\mathrm{A}\text{ and }\mathrm{B}\text{ are two independent events, each with probability }p,(p\ne 0)\text{ then }P(A/A\cup B) \text{is}$

$\begin{array}{l}P\left(\frac{A}{(A\cup B)}\right)=\frac{P\left(A\right)}{P(A\cup B)}=\frac{P\left(A\right)}{P\left(A\right)+P\left(B\right)-P(A\cap B)}\\ \sin ce A and B are independent events P(A\cap B) =P\left(A\right).P\left(B\right)\\ =\frac{p}{2p-p^2}=\frac{1}{2-p}\end{array}$