Q.

 If a+b+c=0, then the solution of the equation a-xcbcb-xabac-x=0 is 

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a

0,±a2+b2+c2

b

0,±32a2+b2+c2

c

0

d

±32a2+b2+c2

answer is C.

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Detailed Solution

axcbcbxabacx=0a+b+cxcba+b+cxbxaa+b+cxacx=0(Σax)1cb1bxa1acx=0x=Σa=0(bx)(cx)a2ccxa}t+b{ab+x}=0or  x2a2+b2+c2+(ab+bc+ca)=0x2Σa2+Σab=0x2Σa212Σa2=0a+b+c=0(a+b+c)2=0Σa2+2Σab=0Σab=12Σa2Or  x=±32Σa2The solution  is x=0  or  ±32Σa2

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