If A+B+C=3600 then cotA4+cotB4+cotC4=

A+B+C=3600 A4+B4+C4=900 cot A4+cot B4+cot C4=cotA4 cotB4 cotC4

If A+B+C=3600 then cotA4+cotB4+cotC4=

A+B+C=3600 A4+B4+C4=900 cot A4+cot B4+cot C4=cotA4 cotB4 cotC4

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If $A + B + C = 360^{0}$ then $\cot \frac{A}{4} + \cot \frac{B}{4} + \cot \frac{C}{4} =$

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$\sin \frac{A}{4} \sin \frac{B}{4} \sin \frac{C}{4}$

$\tan \frac{A}{4} \tan \frac{B}{4} \tan \frac{C}{4}$

$\cot \frac{A}{4} \cot \frac{B}{4} \cot \frac{C}{4}$

$\cos \frac{A}{4} \cos \frac{B}{4} \cos \frac{C}{4}$

answer is D.

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$A + B + C = 360^{0} \frac{A}{4} + \frac{B}{4} + \frac{C}{4} = 90^{0} \cot \frac{A}{4} + \cot \frac{B}{4} + \cot \frac{C}{4} = \cot \frac{A}{4} \cot \frac{B}{4} \cot \frac{C}{4}$

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If A+B+C=3600 then cotA4+cotB4+cotC4=

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If $A + B + C = 360^{0}$ then $\cot \frac{A}{4} + \cot \frac{B}{4} + \cot \frac{C}{4} =$