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Q.

If abc are non-coplanar vectors then 

Statement-1: b×c,c×a,a×b are non-coplanar.

Statement-2: [b×c    c×a a×b]=2[a b c]2

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a

STATEMENT-1 is True, STATEMENT-2 is False
 

b

STATEMENT-1 is True, STATEMENT-2 is True; 
STATEMENT-2 is a correct explanation for STATEMENT-1

c

STATEMENT-1 is False, STATEMENT-2 is True

d

STATEMENT-1 is True, STATEMENT-2 is True; 
STATEMENT-2 is NOT a correct explanation for STATEMENT-1

answer is C.

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Detailed Solution

[b×c c×a a×b]=((b×c)×(c×a))(a×b)=((b(c×a))c(c.(c×a)b)(a×b)=[abc]c(a×b)(c(c×a)=0)=[abc][abc]=[a b c]2

Since R.H.S. is non-zero so is L.H.S. Hence  b × c, c × aa × b are non-coplanar. 

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