If a×b×c×c=a·cR then R=

(a·c)b-(a·b)c×c (a·c) (b×c)-0 ⇒ R=b×c

(a·c)b-(a·b)c×c (a·c) (b×c)-0 ⇒ R=b×c

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If $[a \times (b \times c)] \times c = (a \cdot c) R$ then $R =$

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$c \times a$

$b \times c$

$a \times c$

$c \times b$

answer is B.

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$((a \cdot c) b - (a \cdot b) c) \times c (a \cdot c) (b \times c) - 0 \Rightarrow R = b \times c$

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