If (a×b)×(c×d) = [a b d] c +kd then k =

(a×b)×(c×d) =a b d c-[a b c] d∴ k=-[a b c]

(a×b)×(c×d) =a b d c-[a b c] d∴ k=-[a b c]

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If $(a \times b) \times (c \times d) = [a b d] c + k d$ then $k =$

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$[b a c]$

$[a b c]$

$[b c d]$

$[c b d]$

answer is A.

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$\begin{array}{rcl} (a \times b) \times (c \times d) \\ = & [a b d] c - [a b c] d \\ ∴ k & = & - [a b c] \end{array}$

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