Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

If a=Cosθ-Sinθ; b=Cos3θ-Sin3θ; then 

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

a3-3a+2b=0

b

a3+3a-2b=0

c

a3-3a-2b=0

d

b3-3a+2b=0

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

a=Cosθ-Sinθ; b=Cos3θ-Sin3θ;

a2=1-2 sinθ cosθsinθ cosθ=1-a22b=cos3θ-sin3θ   =(cosθ-sinθ)(1+sinθ cosθ)b=a1+1-a222b=a(3-a2)a3-3a+2b=0

Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring