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If A=cos2π33       sin2π33sin2π33     cos2π33 then   A2017=

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By Expert Faculty of Sri Chaitanya
a
A
b
A2
c
A3
d
A4

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detailed solution

Correct option is D

Let  θ=2π33A=cosθsinθsinθcosθ

A2017=cos2017θsin2017θsin2017θcos2017θ

2017θ=20172π33=122π+8π33cos2017θ=cos4θ;

sin2017θ=sin4θ


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