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Q.

If a=cos8π11+isin8π11, then Rea+a2+a3+a4+a5=

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a

0

b

-12

c

12

d

1

answer is B.

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Detailed Solution

a=cos8π11+i sin8π11

  Rez=z+z2

        Re a+a2+a3+a4+a5 =a+a2+a3+a4+a5+(a+a2+a3+a4+a5)2 =12a+a2+a3+a4+a5+1a+1a2+1a3+1a4+1a5 =12a5a6+a7+a8+a9+a10+a4+a3+a2+a+1 =12a51+a+a2+....+a10-a5 =12a50-a5=-12

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