If ( a, i ) = ( a, j ) = π4then ( a, k ) =

α=π/4 β=π/4 γ=? W.k.t cos2α+cos2β+cos2γ=1 ⇒ 12+12+cos2γ=1 ⇒ cosγ=0 ⇒ π/2

If ( a, i ) = ( a, j ) = π4then ( a, k ) =

α=π/4 β=π/4 γ=? W.k.t cos2α+cos2β+cos2γ=1 ⇒ 12+12+cos2γ=1 ⇒ cosγ=0 ⇒ π/2

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If $(a, i) = (a, j$ ) = $\frac{π}{4}$ then ( $a, k$ ) =

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$\frac{π}{6}$

$\frac{π}{4}$

$\frac{π}{3}$

$\frac{π}{2}$

answer is D.

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$α = π / 4 β = π / 4 γ = ? W . k . t \cos^{2} α + \cos^{2} β + \cos^{2} γ = 1 \Rightarrow \frac{1}{2} + \frac{1}{2} + \cos^{2} γ = 1 \Rightarrow cosγ = 0 \Rightarrow π / 2$

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If $(a, i) = (a, j$ ) = $\frac{π}{4}$ then ( $a, k$ ) =