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Q.

If a=i+j+k b=4i+3j+4k c=i+αj+βk  be linearly dependent vectors and |c¯|=3 then 

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a

α=1,β=±1

b

α=1,β=±1

c

α=1,β=1

d

α=±1,β=1

answer is D.

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Detailed Solution

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Vectors are linearly dependent
1114341αβ=01(3β4α)1(4β4)+1(4α3)=0β=1,c¯|=3|c¯2=31+α2+β2=3α2=1α=±1

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