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If $' a'$ is the length of the side of a cube, the distance between the body centered atom and one corner atom in the cube will be

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a

$\frac{\sqrt{3}}{4} a$

b

$\frac{\sqrt{3}}{2} a$

c

$\frac{2}{\sqrt{3}} a$

d

$\frac{4}{\sqrt{3}} a$

answer is B.

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Detailed Solution

We know that for bcc structure, $r = \frac{\sqrt{3}}{4} a$
Hence, $2 r = \frac{\sqrt{3}}{2} a$
2r represents the distance between the body-centered atom and one corner atom.
Thus, if ‘a’ represents the length of the side of a cube, the distance between the body-centered atom and one corner atom in the cube will be $\frac{\sqrt{3}}{2} a$ .

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