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Q.

If ak is the coefficient of xk in the expansion of (1+x+x2 )n for k = 0,1,2,....,2n then a1+2a2+3a3+....+2n.a2n =

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a

3n

b

n.3n

c

-n.3n

d

-a0

answer is C.

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Detailed Solution

(1+x+x2)n=a0+a1 x+a2 x2+....a2n x2n

Diff with respect to 'x' and Put x=1

n(1+x+x2)n-1 (1+2x)=a1+2a2 x+3a3 x2+....+2n a2n x2n-1n33=a1+2a2+3a3+....+2n a2n

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