If $\alpha$ and $\beta$ are the roots of the equation ${\text{x}}^{\text{2}}\text{+px+2=0}$ and $\frac{1}{\alpha }$ and $\frac{1}{\beta }$ are the roots of the equation ${\text{2x}}^{\text{2}}\text{+2qx+1=0}$ , then $(\alpha -\frac{1}{\alpha })(\beta -\frac{1}{\beta })(\alpha +\frac{1}{\beta })(\beta +\frac{1}{\alpha })$ is equal to