Q.

If α and β are the roots of 2X2+X+3=0, then the equation whose roots are 1-α1+α and 1-β1+β is

see full answer

Want to Fund your own JEE / NEET / Foundation preparation ??

Take the SCORE scholarship exam from home and compete for scholarships worth ₹1 crore!*
An Intiative by Sri Chaitanya

a

2X2+X+3=0

b

2X2-X+3=0

c

2X2+X-3=0

d

2X2-X-3=0

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

α,  β  arerootsof2x2+x+3=0  thenα+β=12,  αβ=32sumofroots=1α1+α+1β1+β=(1α)(1+β)+(1β)(1+α)(1+α)(1+β)=1α+βαβ+1+αβαβ1+(α+β)+αβ=22αβ1+(α+β)+αβ=23112+322412Productofroots=(1α1+α)(1β1+β)=1(α+β)+αβ1+(α+β)+αβ=1+12+32112+32=2+1+321+36432RequiredEquationx2(sumofroots)x+Productofroots=0x2+12x+32=02x2+x+3=0

Watch 3-min video & get full concept clarity
AITS_Test_Package
AITS_Test_Package
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon