$\text{ If }\alpha \text{ and }\beta \text{ be two roots of the equation }{x}^2-64x+256=0\text{ . Then the value of }$${\left(\frac{{\alpha }^3}{{\beta }^5}\right)}^{\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$8$}\right.}+{\left(\frac{{\beta }^3}{{\alpha }^5}\right)}^{\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$8$}\right.}is:$

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