If a×r=b+λa, a·r=3, a=1, b·r=

a×(a×r)=a×b3a-r=a×b ⇒ r =3a-a×bb·r=3(a·b)-0

If a×r=b+λa, a·r=3, a=1, b·r=

a×(a×r)=a×b3a-r=a×b ⇒ r =3a-a×bb·r=3(a·b)-0

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If $a \times r = b + λ a, a \cdot r = 3, |a| = 1, b \cdot r =$

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$3 (a \cdot b)$

$a \cdot b$

$2 (a \cdot b)$

answer is C.

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Detailed Solution

$\begin{array}{rcl} a \times (a \times r) & = & a \times b \\ 3 a - r & = & a \times b \Rightarrow r = 3 a - a \times b \\ b \cdot r & = & 3 (a \cdot b) - 0 \end{array}$

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