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Q.

If α, β are the roots of the equation 6x2-5x+1=0. Then the value of tan-1α+tan-1β is

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a

π/4

b

1

c

0

d

π/2

answer is A.

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Detailed Solution

α+β=56, αβ=16

tan-1α+tan-1β=tan-1(α+β1-αβ)

=tan-1(5/61-(1/6))=tan-1(1)=π4.

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