If $\mathrm{\alpha },\mathrm{\beta }$ are the roots of ${\mathrm{ax}}^2+\mathrm{bx}+\mathrm{c}=0$ then the equation whose roots are $2+\mathrm{\alpha },2+\mathrm{\beta }$ is

$\begin{array}{l}If\alpha ,\beta arerootsoff\left(x\right)=a{x}^2+bx+c=0then\\ TheEquationhaving\alpha +2,\beta +2arerootsisf(x-2)=0\\ \Rightarrow a{(x-2)}^2+b(x-2)+c=0\\ \Rightarrow a{x}^2+4a-4ax+bx-2b+c=0\\ \Rightarrow a{x}^2+(b-4a)x+(4a-2b+c)=0\end{array}$