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Q.

If α,β are the roots of x2px+q=0 ,then α3+β3=

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a

p33pq

b

p3+3pq

c

p22pq

d

p+3q

answer is B.

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Detailed Solution

x2px+q=0 α+β=pαβ=qα3+β3=(α+β)33αβ(α+β)=p33q(p)=p33pq

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