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Q.

If a Sinθ + bCosθ = c then a-btanθb+atanθ=

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a

±b2-c2-a2c

b

±a2+b2+c2b2-c2

c

±b2+c2-a2c

answer is A.

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Detailed Solution

a Sinθ + bCosθ = c

a-btanθb+atanθ=a cosθ-b sinθa cosθ+b sinθ

                      =±a2+b2-c2c

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