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If $A = \tan 1, B = \tan 2, C = \tan 3$ Then descending order of A, B, C

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A, C, B

A, B, C

B, C ,A

C, B, A

answer is C.

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Detailed Solution

$A = \tan 57 °, B = \tan 114 ° (approximately)$

$\begin{array}{l} a n d C = \tan 171 ° \\ \Rightarrow A = \tan 57 °, B = - \tan 66 °, C = - \tan 9 ° \\ \Rightarrow A > C > B \end{array}$

$(\sin c e \tan x i s i n c r e a \sin g i n (\frac{- π}{2}, \frac{π}{2}))$

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