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If $a x^{2} + 2 h x y + b y^{2} = 0 then \frac{d y}{d x} =$

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$- (\frac{a x + h y}{h x + b y})$

$(\frac{a x + h y}{h x + b y})$

$- (a x + h y) (h x + b y)$

$(a x + h y) (h x + b y)$

answer is A.

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Detailed Solution

$\frac{d y}{d x} = \frac{- (\partial f / \partial x)}{(\partial f / \partial y)} = = - \frac{Partial derivative of f w.r.t. x}{Partial derivative of f w.r.t. y}$

$\frac{d y}{d x} = \frac{- (a x + h y)}{h x + b y}$

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