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Q.

If a=xi^+yj^+zk^, then

a×i ^.i^+i^+a×j^.j^+k^+a×k^.k^+i^=

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a

x-y+z

b

x+y+z

c

x+y-z

d

-x+y+z

answer is B.

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Detailed Solution

=0+a i j+0+a j k+0+a k i =a·(i×j)+a·(j×k)+a·(k×i) =a·k+a·i+a·j =z+x+y

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