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Q.

If B, C are square matrices of order n and if A=B+C, BC=CB, C2=0, then for any positive integer pAp+1.

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a

Bp[B+(p+1)C]

b

Bn[B+(p+1)C]

c

Bp[B-(p-1)C]

d

Bp[B+(p-1)C]

answer is A.

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Detailed Solution

 A=B+CAp+1=(B+C)p+1  =C0   p+1Bp+1+C1   p+1BpC+C2   p+1Bp-1C2+...+Cp+1   p+1Cp+1 =Bp+1+C1   p+1BpC+0+0+...      [C2=0C2=C3=...=0] =Bp[B+(p+1)C]

Hence, Ap+1=Bp[B+(p+1)C]

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