Q.

 If C0,C1,C2,..Cn denote the coefficients  of the binomial expansion (1+x)n , then the  value of C1+3C3+5C5++ is 

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a

n2n-1

b

(n+1)2n

c

(n+2)2n-1

d

n2n-2

answer is A.

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Detailed Solution

1+xn=C0+C1x+C2x2+C3x3+....+CnxnDifferentiate both sides n1+xn1=C1+2C2x+3C3x2+...+nCnxn1put  x=1n2n1=C1+2C2+3C3+...+nCnput  x=10=C12C2+3C3+....+1n1nCnAdding the above two equations2C1+3C3+5C5+...=n2n1C1+3C3+5C5+...=n2n2

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