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Q.

If c2=60 and c×i+2j+3k=0 then a value of c.-7i+2j+3k is

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a

42

b

12

c

24

d

122

answer is D.

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Detailed Solution

c×(i+2j+3k)=0  c=λ(i+2j+3k) c2=λ2(1+4+9)    λ2=6014 c.(-7i+2j+3k)=λ(-4+4+9)                              =307×6

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