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Q.

If α,βC are the distinct roots, of the equation x2-x+1=0, then α101+β107 is equal to

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a

0

b

1

c

2

d

-1

answer is B.

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Detailed Solution

x2-x+1=0

  x=1±i32  x=-w  or  -w2

α=-w,  β=-w2

α101=(-w)101=-(w3)33 w2=-w2

β107=(-w2)107=-w214=-(w3)71w=-w

α101+β107=-w2-w=1

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