Q.

If cos-1x+cos-1y+cos-1z=πsec2(u)+sec4(v)sec6(w) where u,v,w are least non-negative angles such that u<v<w, then the value of x2000+y2000+z2000+36πu+v+w=

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answer is 9.

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Detailed Solution

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sec2u,sec4v,sec61,  sec2u+sec4v+sec6we3,  πsec2u+sec4v+sec6w3π, (1)

From (1) & (2) is L.H.S=R.H.S=3π

cos-1x=cos-1y=cos-1z=π

x=y=z=-1 and sec2u=sec4v=sec6w=1

u=π, v=2π, w=3π x2000+y2000+z2000+36πu+v+w=1+1+1+36π6π=9 

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