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Q.

If  cosx+2cos3x=cosy  and sinx+2sin3x=siny then cos 2x=

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Detailed Solution

cos2x+4cos23x+4cosxcos3x=cos2y----(1) and  sin2x+4sin23x+4sinxsin3x=sin2y------(2) Adding1+4+4cos3xx=1 4cos2x=4 cos2x=1

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