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Q.

If domain of|x|+x[x]is(0,  3),thenitsrangeis

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a

(0,  4)

b

[0,  3]

c

[0,  3)

d

[0,  4)

answer is D.

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Detailed Solution

f(x)=|x|+x[x]if  x(0,  3)then  |x|=x[x]={0if  0<x<11if1x<22if  2x<3  f(x)={2xif  0<x<12x1if1x<22x2if2x<3if  0<x<1,if1x<2,if2x<30<2x<1,22x<4,42x<612x1<3,  22x2<4  Range  =(0,   4)

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