Q.

If e1 and e2 are ecentricities of the hyperbolas xy=c2 and x2-y2=a2 then e12+e22=

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a

1

b

e12-e22

c

e12e22

d

4

answer is A.

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Detailed Solution

Since both are rectangular hyperbolas then e1=e2=2

Now e12+e22=2+2=4

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