Q.

If e1 and e2 are the eccentricites of the ellipse x218+y24=1 and the hyperbola x29-y24=1 respectively and (e1 , e2 ) is a point on the ellipse 15x2 + 3y2 = k, then k is equal to ____

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answer is 16.

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Detailed Solution

Given ellipsex218+y24=1 e1=18-418=1418=73 and given hyperbola x29-y24=1 e2=9+49=133 Since (e1, e2) is a point on the ellipse 15x2+3y2=k then 1579+3139=k 105+399=k k=1449=16

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