Q.

If e1 and e2 are the eccentricities of x2a2+y2b2=1 and x2b2+y2a2=1respectively  then

see full answer

Want to Fund your own JEE / NEET / Foundation preparation ??

Take the SCORE scholarship exam from home and compete for scholarships worth ₹1 crore!*
An Intiative by Sri Chaitanya

a

1e12+1e22=1

b

e1=e2

c

1e1+1e2=1

d

e1e2=1

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Let a>b Now eccentricities of given hyperbolas are e1=a2-b2a2 e2=a2-b2a2 e1=e2

Watch 3-min video & get full concept clarity
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon