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Q.

If Λeq∞(NaCl),Λeq∞(KCl) and Λeq∞K2SO4 are 123.7, 147.0 and 152.1Ω−1cm2eq−1, then the Λeq∞Na2SO4 would be

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a

128.8Ω−1cm2eq−1

b

257.6Ω−1cm2eq−1

c

105.5Ω−1cm2eq−1

d

118.6Ω−1cm2eq−1

answer is A.

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Detailed Solution

Λeq∞Na2SO4=Λeq∞(NaCl)+Λeq∞K2SO4−Λeq∞(KCl)=(123.7+152.1−147.0)Ω−1cm2eq−1=128.8Ω−1cm2eq−1

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