Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

If ex=1+t-1-t1+t+1-t and tan y/2=1-t1+t then dydx at t=1/2 is

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

2

b

0

c

12

d

-12

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

ex=1-tan y21+tan y2=tan π4-y2 y=2π4-tan-1 ex dydx=2-11+ex2ex  At t=12,tany2=1-121+12=13y2=π6 y=π3, ex=3-13+1=2-3 dydx=-2(2-3)1+(2-3)2=-2(2-3)8-43=-24=-12 

Watch 3-min video & get full concept clarity

courses

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon