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Q.

If exy=xy, then dydx=

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a

1logx1+logx

b

1xy+xlogx

c

x+yxlog(ex)

d

logx(1+logx)2

answer is D.

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Detailed Solution

exy=xy

(xy).logee=y.logx

xy=y.logx

x=y(1+logx)

y=x1+logx

y'=(1+logx)(1)x(1x)(1+logx)2

=logx(1+logx)2

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