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Q.

If f11(x)+f1(x)+f2(x)=x2  be the differential equation of a curve and let P be the point of maxima then number of tangents which can be drawn from P to x2y2=a2 is/are

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a

1

b

2

c

3

d

0

answer is B.

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Detailed Solution

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At point of maxima  f'(x)=0  and  f"(x)<0
f"(x)=x2f2(x)0
Since the curve is x2y2=a2  and  x2f2(x)0
x12y12<a2
Point lies outside hyperbola
Hence 2 tangents
 

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